Question

A private taxi charges a fare of Rs 260 for a journey of 200 km how much would it travel for Rs 727.50

Answer 1

Answer:

558Km

Step-by-step explanation:

200 km= 260rs

727.50 /260 rs = 2.79

2.79x 200= 558Km

Answer 2

Answer:

Let fixed charge be Rs x and charge per km be Rs y.

⇒x+10y=105...(1)

⇒x+15y=155..(2).

Now From eq 2

⇒15y=155−x

⇒y=155−x / 15 ...(3)

Substituting y from eq3 in eq1

⇒x+ 10(155−x) /15

=105

⇒15x+1550−10x=1575

⇒5x=1575−1550

⇒5x=25

⇒x=5

Substituting x in eq2

⇒5+15y=155

⇒15y=155−5

⇒15y=150

⇒y=10

Hence x=5 and y=10

Fixed charge is Rs.55 and the charge per kilometer is Rs.1010

For 2525 km person have to pay = 5+10×25=255Rs.