Math, asked by shalinigk18, 1 day ago

a probability of getting a doublet of prime in a single throw of pair of dice .

Answers

Answered by Keziah69
1

Prime Numbers doublets are = (2, 2), (3, 3) and (5, 5) = 3 Total . Therefore, → Probability of getting Prime Numbers doublet is = (Favorable outcomes) / (Total outcomes) = (3/36) = (1/12) (Ans.)

Answered by navyaviiid8279
1

Answer is 1/12

Explanation

Prime Numbers doublets are = (2, 2), (3, 3) and (5, 5) = 3 Total . Therefore, → Probability of getting Prime Numbers doublet is = (Favorable outcomes) / (Total outcomes) = (3/36) = (1/12)

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