a probability of getting a even or odd no when two six sided cube rolled at a time
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1/2=0.50000000000000000000000000000000000
∴answwer=0.5000000000000000000
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Hey Mate!!
Here Is Answer
Since 2 fair 6 sided dice (I presume) are being rolled you have 6^2 outcomes. Now If you are taking the values of each die and not adding them up, you want to roll 1,3,5, or 6. So, you have 4*6, outcomes you want, since you get 4 possibilities on one and the other doesn't matter, so 6 possibilities.
4*6= 24 outcomes you want
24/36= 2/3= 67% chance of rolling 1,3,5, or 6
If you do add the die count you need a 3, 5, 6, 7, 8, 9, 10, 11, or 12.
So, you have
•3: 2+1, 1+2
•5: 1+4, 2+3, 3+2, 4+1
•6: 1+5, 2+4,3+3, 4+2, 5+1
•7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1
•8: 2+6, 3+5, 4+4, 5+3, 6+2
•9: 3+6, 4+5, 5+4, 6+3
•10: 4+6, 5+5, 6+4
•11: 5+6, 6+5
•12: 6+6
So, you have 32 outcomes you want out of 36 possibilities(6^2).
So 32/36= 8/9= 89%
Regards Vishal___________(BhamBhamBhole)
_-_-_
#BeBrainly✌✌
Here Is Answer
Since 2 fair 6 sided dice (I presume) are being rolled you have 6^2 outcomes. Now If you are taking the values of each die and not adding them up, you want to roll 1,3,5, or 6. So, you have 4*6, outcomes you want, since you get 4 possibilities on one and the other doesn't matter, so 6 possibilities.
4*6= 24 outcomes you want
24/36= 2/3= 67% chance of rolling 1,3,5, or 6
If you do add the die count you need a 3, 5, 6, 7, 8, 9, 10, 11, or 12.
So, you have
•3: 2+1, 1+2
•5: 1+4, 2+3, 3+2, 4+1
•6: 1+5, 2+4,3+3, 4+2, 5+1
•7: 1+6, 2+5, 3+4, 4+3, 5+2, 6+1
•8: 2+6, 3+5, 4+4, 5+3, 6+2
•9: 3+6, 4+5, 5+4, 6+3
•10: 4+6, 5+5, 6+4
•11: 5+6, 6+5
•12: 6+6
So, you have 32 outcomes you want out of 36 possibilities(6^2).
So 32/36= 8/9= 89%
Regards Vishal___________(BhamBhamBhole)
_-_-_
#BeBrainly✌✌
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