Question

A problem in probability was given to three ca students a b and c whose chances of solving

Answer 1

Answer:

The answer is one

Step-by-step explanation:

S={a, b, c}

n(S)= 3

P(S)= 3/3

= 1

Answer 2

Answer:

11/15

Step-by-step explanation

p(A)=1/3   P(B)=1/5   P(C)=1/2

p(hitting the target once they both try)=P(A∪B∪C)

=P(A)+P(B)+P(C)-P(A∩B)-P(B∩C)-P(C∩B)+P(A∩B∩C)

since theyare independent P(A∩B)=P(A)XP(B) =1/3 x 1/5=1\15

                                              P(B∩C)=P(B)XP(C)=1/5 x 1/2= 1/10

                                              P(C∩A)=P(C) x P(A)=1/2 x 1/3 =1/6

                                         P(A∩B∩C)=P(A)XP(B)XP(C)=1/3 x 1/5x 1/2=1/30

P(A∪B∪C) =1/3+1/5+1\2-  1/15 - 1/10 - 1/6 + 1/30

=31/30-2/30-3/30-5/30+1/30( by making the denominator same )

=22/30= 0.733

in the options 11/15=0.7333

hence answer =11/15