Chemistry, asked by drMythic, 7 months ago

A procedure calls for 100 cm3 of 20.0 % H2SO4, density 1.14 g/cm3. How much concentrated acid, of density 1.84 g/cm3 and containing 98.0 % H2SO4 by weight, must be diluted with water to prepare 100 cm3 acid of the required strength?

Answers

Answered by amitkumar9266
4

Answer:

M of the diluted stuff is

1.14 g/mL x 1000 mL x 0.20 x 1/98 = 2.33M

M of the strong stuff is

1.84 x 1000 x 0.98 x 1/98 = 18.4M

Then use the dilution formula.

mLA x MA = mLB x MB

100 x 2.33 = mLB x 18.4M

Solve for mL B. I obtained approx 13 mL

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