A procedure calls for 100 cm3 of 20.0 % H2SO4, density 1.14 g/cm3. How much concentrated acid, of density 1.84 g/cm3 and containing 98.0 % H2SO4 by weight, must be diluted with water to prepare 100 cm3 acid of the required strength?
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M of the diluted stuff is
1.14 g/mL x 1000 mL x 0.20 x 1/98 = 2.33M
M of the strong stuff is
1.84 x 1000 x 0.98 x 1/98 = 18.4M
Then use the dilution formula.
mLA x MA = mLB x MB
100 x 2.33 = mLB x 18.4M
Solve for mL B. I obtained approx 13 mL
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