Math, asked by shreyamenon4690, 1 year ago

A Product is supported each week by the same three Product supporters. Last month the first supporter took 440 calls, the second took 360 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three supporters each increase their work proportionately, how many more calls will the second supporter take this month than last month ?

Answers

Answered by Anonymous
2
\huge{Hey Mate!!!}

☆☞ Here is ur answer ☜☆

✔✔ 1st supporter recieve 440 calls 
2nd supporter recieve 360 calls 
3rd supporter recieve 300 calls

So total calls = 1100 calls ; 
Calls this month= 1500 
So remaining calls to be distributed is 400

So Now Ratio 1st:2nd:3rd ==> 440:360:300
=> 22:18:15

Now No. of More Calls 2nd supporter will get => [18/(22+18+15)] x 400
=> (18/55) x 400 
=> 131 Calls
So 131 more Calls than last month.



HOPE IT HELPS!
Answered by Pakhi44
0
Heya..!!!
_______


5

Q:

A Product is supported each week by the same three Product supporters. Last month the first supporter took 440 calls, the second took 360 calls, and the third took 300 calls. This month the job will consists of 1500 calls. If the three supporters each increase their work proportionately, how many more calls will the second supporter take this month than last month ?

A) 131 callsB) 160 callsC) 491 callsD) 600 calls

Answer:   A) 131 calls 

Explanation:

1st supporter recieve 440 calls 
2nd supporter recieve 360 calls 
3rd supporter recieve 300 calls
So total calls = 1100 calls ; 
Calls this month= 1500 
So remaining calls to be distributed is 400
So Now Ratio 1st:2nd:3rd ==> 440:360:300
=> 22:18:15
Now No. of More Calls 2nd supporter will get => [18/(22+18+15)] x 400
=> (18/55) x 400 
=> 131 Calls





Thanks :)
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