Question

A proectile is launched at initial velocity of 12 m/s and an angle of 27 degree.
a. what is the maximum height reached by a projectilep?
b. what is the time taken by the projectile?​

Answer 1

Answer:

time taken = 2usinTheta /g

max height = u^2 sin^2 theta/ 2g

please put in the values and evaluate

take g as 10

also

the proofs are simple of above equations. do let me know if u have any doubt