Math, asked by damarene, 10 months ago

A professional gambler reported that at the end of the first race at the track he had doubled his money. He bet $31 on the second race and tripled the money he came with. He bet $51 on the third race and quadrupled his original bankroll. He bet $84 on the fourth race and lost it, but still had $40 left. With how much money did he start?

Answers

Answered by SmartBoy497
6

Step-by-step explanation:

  1. 16
  2. 32
  3. 64
  4. 124= 84 which he lost+40 which he has left
Answered by Qwafrica
0

He started with the amount of $31.

Given:

  • A professional gambler reported that at the end of the first race at the track he had doubled his money.
  • He bet $31 on the second race and tripled the money he came with.
  • He bet $51 on the third race and quadrupled his original bankroll.
  • He bet $84 on the fourth race and lost it, but still had $40 left.

To find:

The amount of money he started with.

Solution:

We can simply solve this question by using the following method.

Now, we can assume we started with the amount of x.

At the end of the first race, he doubled his money, so that is 2x.

He bet $31 on the second race and tripled the money he came with, so his money became 3x.

He bet $51 on the third race and quadrupled his original bankroll, so that is 4x.

And now,

He bet $84 on the fourth race and lost it, but still had $40 left.

So we get,

4x - 84 = 40

⇒ 4x = 84 + 40

⇒ 4x = 124

⇒ x = 124/4

∴ x = 31

Hence, he started with the amount of $31.

#SPJ2

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