a program to check whether a number is pronic or not
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Answered by
2
int main(){
//1
int no;
int i;
int flag = 0;
//2
printf("Enter a number to check : "); scanf("%d",&no);
//3
for(i=0; i<=no ;i++){ //4 if(i*(i+1) > no){
break;
}
//5
if(i*(i+1) == no){
printf("The input number is a Pronic number.\n");
flag = 1;
break;
}
}
//6
if(!flag){
printf("The input number is not a Pronic number.\n");
}
}
I hope it helps!
//1
int no;
int i;
int flag = 0;
//2
printf("Enter a number to check : "); scanf("%d",&no);
//3
for(i=0; i<=no ;i++){ //4 if(i*(i+1) > no){
break;
}
//5
if(i*(i+1) == no){
printf("The input number is a Pronic number.\n");
flag = 1;
break;
}
}
//6
if(!flag){
printf("The input number is not a Pronic number.\n");
}
}
I hope it helps!
2adi:
thanks...
Answered by
1
- A pronic number is a type of number which is a product of any two consecutive integers.
- It's a Java program i.e. the following program is written in Java programming language.
import java.util.Scanner;
public class PronicNumber
{
public static void main(String brain[])
{
Scanner promo=new Scanner(System.in);
System.out.println("Enter a number to be checked.");
int n=promo.nextInt();
for(int k=1;k<=n;k++)
{
if(n%k==0)
{
if((k+1)*i==n||(k-1)*i==n)
{
System.out.println("Entered number is Pronic.");
break;
}
else
{
System.out.println("No, the number is not Pronic number.");
break;
}
}
}
}
}
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