Question

A project is projected horizontally from point A with velocity 20m/s. Horizontal range (BC) of projectile is​

Answer 1

Given : velocity 20m/s  ;  height H = 20 m

Horizontal range (BC) of projectile is​ given by ,

         

           $R = u*\sqrt{\frac{2H}{g} }$

⇒    $R = 20*\sqrt{\frac{2*20}{10} }$

            R  = 40 m.

Hope this helps you !!

Answer 2

Given:

Initial horizontal velocity = 20m/s

To find:

Horizontal range of projectile (BC)

Solution:

Let the time=t when the object touched the ground.

And initial vertical velocity in vertical direction = 0

And we know that:

S = ut + 1/2at^2

20 = 1/2* 10* t^2

t = 2 sec

Now, lets come to horizontal direction, where the initial velocity is 20 m/s.

S = ut + 1/2 at^2

Since the acceleration in horizontal direction is 0.

S = 20*2

S = 40 m

Therefore, the horizontal range (BC) of projectile is 40m.