Question

A projectile can have the same range R for two angles of projection.If T1 and T2 be the times of flights in the two cases, then the product of the two time of flights is directly proportional to​

Answer 1

For same range angle of projection should be θ and 90 - θ So, time of flight t1 = 2u sin θ/g and t2 = 2u sin(90- θ)/g = 2u cosθ/g By multiplying =   t1t2  = 4u2 sinθ cosθ/g2