Question

A projectile can have the same range R for two angles of projection. If t1 and t2 be the time of flight in the two cases, then prove that t1.t2=(2*r)/g SPAM ANSWERS WILL BE REPORTED

Answer 1

In case of projectile motion, Range R of a projectile is governed by eqn R=(u²Sin2∅)/g. Sin2∅=Sin(180–2∅)=Sin2(90-∅). So for same range could there be two angles of projection ie ∅ and (90-∅). If T1 and T2 are the time of flight in two cases=>T1=2uSin∅/g and T2=2uSin(90-∅)/g=2uCos∅/g.