Question

. A projectile can have the same range R for two angles of projection. If h1 and h2 be the maximum height in the two cases, then :​

Answer 1

Answer:

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Explanation:

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Answer 2

Explanation:

Same range (R) will be obtained when the angles of projection are, 30° and 60°

$h(1) = \: \frac{ {(u \sin( \alpha )) }^{2} }{2g} \: \: and \\ h(2) \: = \frac{ ({u \sin( \beta ) )}^{2} }{2g}$

Therefore,

$\frac{h(1)}{h(2)} = \frac{ { (\sin( \alpha ) )}^{2} }{ {( \sin( \beta ) )}^{2} } \\ => \frac{( { \frac{1}{2} )}^{2} }{( { \frac{ \sqrt{3} }{2} )}^{2} } \\ = \frac{1}{3}$

Hence, h(1) : h(2) = 1 : 3