Question

A projectile cross
half it maximum height at a certain time and again 10 second later. Calculate the maximum height. If the angle of projection was 30 degree, Calculate the maximum range of projectile as well as horizontal distance it travelled in the above 10 second​

Answer 1

Answer:

h = v 0 y 2 2 g . This equation defines the maximum height of a projectile above its launch position and it depends only on the vertical component of the initial velocity

Answer 2

Explanation:

h=voy22g.this defines the maximum height