Question

A projectile fired from bottom of inclined plane strikes the plane with horizontal velocity. If angle of projection is theta, what will be angle of inclined plane with horizontal. 50 POINTS FOR THIS ANSWER, PLS, ITS ANSWER FAST.

Answer 1

Answer:

Explanation:

Velocity perpendicular to the  inclined  plane u  v  =usin(α−β)

a=−gcosβ

t=T

s=0

0=usin(α−β)T−  

2

1

​  

(gcosβ)T  

2

 

⇒T=  

gcosβ

2usin(α−β)

​