Question

a projectile fired with initial velocity u at some angle theta has a range r if the initial velocity be doubled at the angle theta the range

Answer 1

solved....... ........

Answer 2

Answer:

If the initial velocity be doubled at the angle θ the range will become four times.

Explanation:

It is given that, a projectile fired with initial velocity u at some angle θ has a range r.

The range of a projectile is given as :

$r=\dfrac{v^2sin\ 2\theta}{g}$

Range is directly proportional to the velocity.

If the initial velocity be doubled at the angle θ the range will be R say. So, range will be :

$R=\dfrac{(2v)^2sin\ 2\theta}{g}$

$R=4(\dfrac{v^2sin\ 2\theta}{g})$

So, R = 4 r

Hence, if the initial velocity is doubled its range will become four times.