A projectile has a range of 50 m and reaches a maximum height of 10 m with steps
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We know that Horizontal range R = u^2sin 2theta/g --------------- (1)
We know that Maximum height H = u^2sin^2 theta/2g ------------- (2)
On solving (1) and(2) we get
R/H = 4/tan theta --------------------- (3)
Given, R = 50m, Height = 10, substitute in (3), we get
50/10 = 4/tan theta
tan theta =4/5
theta = 38.6598 degrees.
Hope this helps!
We know that Maximum height H = u^2sin^2 theta/2g ------------- (2)
On solving (1) and(2) we get
R/H = 4/tan theta --------------------- (3)
Given, R = 50m, Height = 10, substitute in (3), we get
50/10 = 4/tan theta
tan theta =4/5
theta = 38.6598 degrees.
Hope this helps!
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