Question

a projectile has maximum range of 400 metre if it is pushed up smooth inclined plane of angle 30 degree with the same speed the distance travelled by it along the inclined plane will be​

Answer 1

Dear Student,

◆ Answer -

s = 400 m

◆ Explanation -

Maximum range is obtained at 45° angle of production.

Rmax = u^2 / g

400 = u^2 / 10

u^2 = 4000

u = 20√10 m/s

Acceleration along inclined plane is -

a = -gsinθ

a = -10 × sin30°

a = -10 × 1/2

a = -5 m/s^2

Let s be distance travelled by projectile on inclined plane.

v^2 = u^2 + 2as

0^2 = 4000 + 2×(-5)×s

s = 4000 / 100

s = 400 m

Therefore, distance travelled by projectile on inclined plane is 400 m.

Thanks dear...

Answer 2

Answer:

Maximum range is obtained at 45° angle of projection.

• Rmax = u² / g

• 400 = u² / 10

• u² = 4000

• u = 20√10 m/s

Acceleration along inclined plane is

• a = -gsinθ

• a = -10 × sin30°

• a = -10 × 1/2

• a = -5 m/s²

Let s be distance travelled by projectile on inclined plane.

• v² = u² + 2as

• 0² = 4000 + 2×(-5)×s

• s = 4000 / 100

• s = 400 m

Final Answer:-

• Distance travelled by projectile on inclined plane is 400 m.