Question

A projectile has the maximum height of 200 m if the projectile is thrown up of theta =45° with same speed.what is the distance covered by it along the plane.​

Answer 1

H= u²sin²45/2g

H=u²/4g

u²=8000

R=u² 2 sin 45. cos45/g

R=u²/g

R=8000/10

R=800 m

or

R=4H max

R=4×200

R=800m

I hope this helps ( ╹▽╹ )