Question

A projectile initally at height h0 above the ground, is fired horizontally and strikes the ground a horizontal distance r from

Answer 1

Answer:

Brainly.in

Answer:

9.528 m/s²

Explanation:

Since both the projectiles follow the same path and same trajectories, their maximum height and range will be same.

Let the acceleration due to gravity on the planet be g'

Let u = 5 m/s and u' = 3 m/s

Equating the ranges of both the projectiles we get

\frac{u^{2}sin2\theta }{g} =\frac{u'^{2}sin2\theta }{g'}

or, g'=g\frac{u'^{2} }{u^{2} }

or, g' = 9.8 × \frac{3^{2} }{5^{2} }

or, g' = 9.8 × \frac{9}{25}

⇒ g' = 3.528 m/s²

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