A projectile is fired a velocity of 150 meters per second at an angle of 30 degrees with
the horizontal. What is the magnitude of the vertical component of the velocity at the
time the projectile is fired?
Answers
Answered by
1
Answer:
75m/s
Explanation:
Since t=0
V(vertical) = vsinθ
= 150*sin30°
=150*1/2
=75
Answered by
0
the anwer is 75m/s
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