Question

a projectile is fired and covered a maximum range "R".calculate the maximum height h in terms of R.S

Answer 1

Answer:

Let u be the initial velocity of projection and θ be the angle of the projectile.

Range of the projectile: R=gu2sin2θ ....(1)

Maximum height of the projectile: H=2gu2sin2θ ....(2)

Step2: Angle of projectile calculation .

Dividing equation (2) by (1)

⇒ RH=2sin2θsin2θ =4sinθ cosθsin2θ =4tanθ

⇒ 5010=4tanθ

⇒ θ=tan−1(54)

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