Question

a projectile is fired at a angle of 30 with the the velocity of 10 ms at what angle with the vertical should it be fired at the maximum range

Answer 1

Hii mate

R=u^2sin2theeta / g

=(10)^2×sin2×60°/ 9.8
=100 × cos 30° / 9.8
=(100 ×root3 / 2) /9.8
=50 root 3 / 9.8
=5.1020 ×root 3

[root 3=1.73]

R=8.82646m

hope it helps you
thank you

Answer 2

Answer:

range = $\frac{ v^{2}sin(2 \alpha)}{g}$

where α=angle with horizontal.

we get α=45° for maximum range.

So angle with vertical = 90° - 45° = 45°

v = 10m/s

Range = 10²×sin(60)/9.8 = 8.8m

maximum range = 10²×sin(90)/9.8 =