Question

A projectile is fired at an angle 60° to the horizontal with initial velocity of 800 m/s then,​

Answer 1

$\huge \underline{ \pmb{ \red{Answers-}}}$

T = 1384 s

R = 27712 m

Ta = 692 s

$\huge{ \underline{ \pmb{ \red{Explaination-}}}}$

$\bullet{ \pmb{ \ \blue{Given-}}}$

u = 800m/s

θ = 60°

$\bullet \: { \pmb{ \blue{Solution-}}}$

$\bold{a) \: Time \: of \: flight-}$

T = 2usinθ/g

T = 2×800×sin60

T = 1384 s

$\bold{b) \: Horizontal \: range - }$

R = u^2sin2θ/2g

R = 800^2 × sin120 / (2×10)

R = 32000×0.866

R = 27712 m

R = 27 km

$\bold{c) \: Time \: of \: ascent-}$

Ta = usinθ/g

Ta = 800×sin60

Ta = 692 s