Physics, asked by swetha54321, 8 months ago

A projectile is fired at an angle. It covers a height H and range R. The same projectile is fired again at an another angle and this time it reaches 3 times of its height with the same range R. Find both the angles.​

Answers

Answered by BrainlySmile
3

Answer- The above question is from the chapter 'Kinematics'.

Concept used: 1) H = \dfrac{u^{2} \: sin^{2} \theta}{2g}

2) R = \dfrac{u^{2} \: sin 2 \theta}{g}

Given question: A projectile is fired at an angle. It covers a height H and range R. The same projectile is fired again at an another angle and this time it reaches 3 times of its height with the same range R. Find both the angles.

Answer: (Please see the attachment.)

Attachments:
Answered by Anonymous
0

Answer- The above question is from the chapter 'Kinematics'.

Concept used: 1) H = \dfrac{u^{2} \: sin^{2} \theta}{2g}H=

2g

u

2

sin

2

θ

2) R = \dfrac{u^{2} \: sin 2 \theta}{g}R=

g

u

2

sin2θ

Given question: A projectile is fired at an angle. It covers a height H and range R. The same projectile is fired again at an another angle and this time it reaches 3 times of its height with the same range R. Find both the angles.

Answer: (Please see the attachment.)

Attachments:
Similar questions