Question

A projectile is fired at an angle of 30 degree with the horizontal with velocity 10m/s. At what angle

with the vertical should it be fired to get maximum range..
Answer I'll mark u as the brainliest​

Answer 1

Answer:

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Explanation:

Range =  [v² sin(2$\alpha$)] / g

where $\alpha$ = angle with horizontal.

we get $\alpha$ = 45° for maximum range.  

So angle with vertical = 90° - 45° = 45°

v = 10m/s

Range = 10²×sin(60)/9.8 = 8.8m

maximum range = 10²×sin(90)/9.8 = 10.2m

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Answer 2

Answer:

Range =  [v² sin(2)] / g

where  = angle with horizontal.

we get  = 45° for maximum range.  

So angle with vertical = 90° - 45° = 45°

v = 10m/s

Range = 10²×sin(60)/9.8 = 8.8m

maximum range = 10²×sin(90)/9.8 = 10.2m

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