A projectile is fired at an angle of 30° with the horizontal so that the initial vertical velocity is 80m/s. If t be the time of flight of the projectile, what is the velocity at time t=t/4
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time t= 2usintheta/g
t=8sec
t/4= 2 sec
vy= 40-10*2= 20 j
vx= 40√3 i
v= 40√3i+ 20j
|v|= √(vx^2+vy^2)
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