a projectile is fired at an angle of 30° to the horizontal such that the vertical component of its initial velocity is 80 m/s. its time of flight is t. its velocity at the moment , has a magnitude of nearly
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uy = 80 m/s
θ = 30
uy = usinθ
u = 80×2 = 160 m/s
At the most height vy = 0
vy = uy + aT/2
0 = 80 −10T/2
T = 16 s
Velocity after time T/4
vy = 80−10×16/4
vy = 40 m/s
Horizontal component
ux = u cosθ= 80√3m/s
V = √vx^2+vy^2
V = 80 m/s
θ = 30
uy = usinθ
u = 80×2 = 160 m/s
At the most height vy = 0
vy = uy + aT/2
0 = 80 −10T/2
T = 16 s
Velocity after time T/4
vy = 80−10×16/4
vy = 40 m/s
Horizontal component
ux = u cosθ= 80√3m/s
V = √vx^2+vy^2
V = 80 m/s
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