Question

A.projectile.is..fired at an.angle of 45 with the horizontal.elevation angle of the projectile at its highest point as seen frm the point of projection

Answer 1

The elevation angle of the projectile is surrounds at highest point and it seems from the point of projection.

The velocity is Vy=v sin theta and V=sin 45=v/root (2).

In fact, the triangle because as in the question the body with at highest point so theta is 45.

The triangle is perpendicular as height based as R/2.