a projectile is fired at an angle theta with the horizontal obtain expression for the 1.maximum height attained
2. time of flight
3. the horizontal range
Answers
Answered by
10
hmax = u^2sin^2tetha /2g
t = 2usin tetha /g
R = u^2 sin2 tetha /g
saha1234:
ohkk i will help u
firstly draw the diagram
then by using equation of motion s=ut +1/2 at ^2
firstly calculate time as we know that time should be along yaxis
also take sy = 0 and uy = usin tetha ; a = -g
and in hmax case : use equation of motion v^2 - u^ 2 = 2as
take vy=0 ; uy = usin tetha ; a = -g
and in case of range as it is taken along x axis use same eqn s = ut +1/2 at ^2
also take sx = R ; ux = u cos tetha and ax = 0 and put t = 2u sintetha /g
i hope now u will understand
Similar questions