Question

A projectile is fired at some angle with speed
such that it crosses two walls of equal heich
symmetrically as shown. The angle of projection
with horizontal is
(1) 53°
(3) 45°
(2) 37°
(4) 60°​

Answer 1

Answer:

Explanation:

From 2 to 3 s , the projectile has travelled a horizontal distance of 120 m . Thus, horizontal velocity is 120 m/s .

The horizontal velocity does not change .

Therefore, initial horizontal velocity is also 120 m/s

Vertical velocity at t = 2 s is gT/2 = 9.8/2 = 4.9 m/s

( using time of flight ,( from 2s to 3 s ) T = 2 u sin theta/ g )

Initial vertical velocity is 4.9 + gt = 4.9 + 9.8 *2

24.5 m/s

tan θ = 24. 7/ 120

θ = 11.54°

Answer 2

Answer:

Option 1

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