A projectile is fired from surface of earth with initial speed of 10 km/s. If the radius of earth is 6400 km, then how high will it go from earth surface
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u = 10km/s = 10000m/s
v = 0
a = -9.8m/s²
2as = v² - u²
2×-9.8×s = -100000000
s = 5102040.816m = 5102.040km
v = 0
a = -9.8m/s²
2as = v² - u²
2×-9.8×s = -100000000
s = 5102040.816m = 5102.040km
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