Question

A projectile is fired from the surface of the earth with a velocity of 5m/s an

Answer 1

Answer:

3.5 m/s

Explanation:

Given

A projectile is fired from the surface of the earth with a velocity of 5 m s-1  and angle θ  with the horizontal. Another projectile fired from another planet with a velocity of 3 m s-1 at the same angle follows a trajectory which is identical with the trajectory of the projectile fired from the earth. The value of the acceleration due to gravity on the planet is (in m s-2) is (Given g = 9.8 ms

We know that  

The equation of trajectory is

y = x tan θ – g x^2 / 2 μ^2 cos^2 θ

where θ is the angle of projection and u is the velocity with which projectile is projected. Now for equal trajectories and same angles of projection we get

g / u^2 = constant

According to the question

9.8 / 5^2 = g’ / 3^2

Where g’ is acceleration due to gravity  

So g’ = 9.8 x 3^2 / 5^2

   g’ = 9.8 x 9 / 25

  g’ = 3.5 m / s^2

Answer 2

Answer:

I hope it helps you............