Question

A projectile is fired from the surface of the Earth with a speed of 200 meters per second at an angle of 30°
above the horizontal. If the ground is level, what is the maximum height reached by the projectile?
(A) 5 m (B) 10 m (C) 500 m (D) 1,000 m (E) 2,000 m

Answer 1

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Answer 2

$\underline{ \boxed{ \bold{ \rm{ \huge{ \purple{ \mathfrak{Answer}}}}}}} \\ \\ \star \rm \: \red{Given} \\ \\ \implies \rm \: velocity \: of \: projection = 200 \frac{m}{s} \\ \\ \implies \rm \: angle \: with \: ground = 30 \degree \\ \\ \star \rm \: \red{To \: Find} \\ \\ \implies \rm \: maximum \: height reached \: by \: body \\ \\ \star \rm \: \red{Calculation} \\ \\ \dagger \: \underline{ \boxed{ \bold{ \rm{ \pink{H} = \blue{ \frac{ {u}^{2} { \sin }^{2} \theta }{2g} }}}}} \: \dagger \\ \\ \therefore \rm \: H = \frac{ ({200})^{2} \times {sin}^{2} 30 \degree }{2 \times 10} \\ \\ \therefore \rm \: H = \frac{40000 \times \frac{1}{4} }{20} \\ \\ \therefore \: \boxed{ \bold{ \rm{ \orange{H = 500 \: m}}}} \: \red{ \star}$