Question

a projectile is fired horizontally from a height of 19.62cm from the ground and reaches the ground at a horizontal distance of 49 m.The initial velocity is approximately
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Answer 1

Explanation:

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Answer 2

Answer:

The initial velocity is 245 m/s.

Explanation:

Given that,

Height = 19.62 cm

Distance = 49 m

We need to calculate the time

Using equation of motion

$S_{y}=u_{y}t+\dfrac{1}{2}gt^2+h_{0}$

Put the value into the formula

$0=0-\dfrac{1}{2}\times9.8\times t^2+19.62\times10^{-2}$

$t^2=\dfrac{19.62\times10^{-2}}{4.9}$

$t=\sqrt{0.04}$

$t=0.2\ sec$

We need to calculate the initial velocity

Using equation of motion

$S_{x}=u_{x}t$

Put the value into the formula

$49=u_{x}\times0.2$

$u_{x}=\dfrac{49}{0.2}$

$u_{x}=245\ m/s$

Hence, The initial velocity is 245 m/s.