A projectile is fired horizontally from an inclined plane of inclination 45 with speed 50. if g=10 the range measured along the incline is
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Answered by
2
Answer:
The range is 250 m
Explanation:
According to the problem the projectile making angle of 45 degree and the speed of the projectile is 50 m/s
Therefore to calculate the range of the projectile at g= 10
let range = d
the speed of the projectile is u = 50 m/s
θ= 90°
Therefore,
d =u^2sin2θ/g=(50)^2 sin90°/10
=250 m
Answered by
0
Answer:
Answer:
The range is 250 m
Explanation:
According to the problem the projectile making angle of 45 degree and the speed of the projectile is 50 m/s
Therefore to calculate the range of the projectile at g= 10
let range = d
the speed of the projectile is u = 50 m/s
θ= 90°
Therefore,
d =u^2sin2θ/g=(50)^2 sin90°/10
=250 m
Explanation:
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