Question

a projectile is fired horizontally with velocity of 98 m/s from the top of the hill 490m high find the velocity with which the projectile strikes the ground

Answer 1

In a horizontal projection we have the vertical components and the horizontal components.

The horizontal velocity is constant but for the vertical displacement there is acceleration due to gravity.

We can find the final velocity from the following formula.

V² = U² + 2gs

Where :

V = Final velocity

U = initial velocity = 98m/s

g = acceleration due to gravity = 10

S = Displacement = 490 m

Doing the substitution :

V² = 98² + 2 × 10 × 490

V² = 19404

V = √19404

V = 139.30 m/s

Answer 2

Answer:

Explanation:

See the answer in the attachment