Question

A projectile is fired horizontaly with a velocity of 98m/s from the top of a hill 490m high . Find
1. Time to reach ground
2. The speed with which it hits the ground​

Answer 1

Answer:

From equations of motion

Taking horizontal component,intial velocity in horizontal direction is 98 while in vertical its 0

⟹v=

u

2

+2gh

=

98

2

+2×9.8×490

⟹v=98

2

m/s

y=

2

1

gt

2

⟹t=

g

2h

=

9.8

2×490

⟹t=10s

solution

Answered