a projectile is fired with 50m/s at an angle of 37⁰ find the time of ascent
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Answer:
time of ascent ta=3sec
Explanation:
we know that equation of motion
v=u+at
a=g=acceleration due to gravity=10m/S2
u=intial velocity=50m/s(given)
teta angle=37 degrees
final velocity must be zero because it will touches any object and becomes rest
so the vertical projectile will be sinteta
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