Question

A projectile is fired with 50m/s at an angle of 37º find the time of ascent.
Tf two​

Answer 1

Need to FinD :-

• The time of ascent of the projectile.

$\red{\frak{Given}}\begin{cases}\textsf{ A projectile is fired at an angle of } \sf 37^{\circ} .\\\textsf{ The velocity of projection is 50m/s .}\end{cases}$

We know that the time of ascent of a projectile , when a body is projected at an angle theta , and with a Initial velocity of u is given by , u sinθ/g . This is also the Formula of time of descent . And the total time of flight is given by 2u sinθ / g .

• Using Formula of Time of ascent :-

$\sf\dashrightarrow Time_{(ascent)}= \dfrac{u\ sin\theta}{g} \\\\\sf\dashrightarrow Time_{(ascent)}= \dfrac{2 \times 50m/s \ sin37^{\circ} }{10m/s } \\\\\sf\dashrightarrow Time_{(ascent)}= 2\times 5 \times \dfrac{3}{5} s \\\\\sf\dashrightarrow Time_{(ascent)}= 2\times 3 s \\\\\sf\dashrightarrow\underset{\blue{\sf Required\ time }}{\underbrace{\boxed{\pink{\frak{ Time_{(ascent)}= 6s }}}}}$