Question

A projectile is fired with a velocity v0 at an angle of 90° with an inclined plane (having an angle of inclination theta with the horizontal). Vertical displacement of the projectile when it strikes the incline for the first time is​

Answer 1

Given:

Velocity = v0

Angle on inclined plane = 90

To Find:

Vertical displacement of the projectile.

Solution:

ux = 0, thus ax = gsinθ  

uy = u, thus ay = -gcos θ

Y = 0 = uyt + 1/2ayT²

= T = 2uy/ay

= 2u/gcos θ

R = uxt + 1/2axT²

= 1/2gsinθ   ( 2u/gcos θ )²

= 2u²tanθ /gcosθ

​Answer: The vertical displacement is 2u²tanθ /gcosθ