Question

a projectile is fired with horizontal velocity of 330 metre per second from the top of a cliff 18 hai how long will it take to strike the level ground at base of clip with what velocity will it strike

Answer 1

Explanation:

when projectile is projected then its range R

1

=

g

u

2

sin2θ

when particle collide with ground then, restitution e=

u

1

−u

2

v

2

−v

1

e=

−usinθ−0

0−v

2

this gives, v

2

=eusinθ

Now for range , since angle of projection remains same r

2

=

g

2u

y

u

x

=e

g

u

2

sin2θ

Therefore Range from point of projection will be :R+R

1

+R

2

=

g

u

2

sin2θ

(1+e)