Question

A projectile is fired with horizontal velocity of 330m/s from the top of a cliff 80m high. How long will it strikes the level ground at the cliff? With what velocity will it strike ?

Answer 1

Answer:

Since the (vertical) velocity of the ball is given by (assuming g≈ constant)

v(t)=dsdt=v0−gt,

the speed of the object when hits the ground is the velocity at time t∗, where t∗ is the value of t when s(t)=sG=0 (if your reference system is placed at s=sG=0 for the ground).

Answer 2

Answer:

1320

Explanation:

R+uT

where T=underoot2H/g