Question

A projectile is fired with initial velocity 10 m/sec making an angle 60° with horizontal. What
velocity at max, height?​

Answer 1

Answer:

5 m/s                  [∵ v = u cosθ]

Explanation:

Given:

u = 10 m/s

θ = 60°

At maximum height vertical component of velocity is zero

so only horizontal component is present

⇒ v = u cosθ

      = 10 × cos60°

      = 10 × 1/2

      = 5 m/s

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