Question

A projectile is fired with initial velocity of 90m/s to hit a ground level target. its maximum
horizontal range will be:
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Answer 1

Answer:

Since the (vertical) velocity of the ball is given by (assuming g≈ constant)

v(t)=dsdt=v0−gt,

the speed of the object when hits the ground is the velocity at time t∗, where t∗ is the value of t when s(t)=sG=0 (if your reference system is placed at s=sG=0 for