Physics, asked by babu9800, 1 year ago

A projectile is fired with velocity u at an angle theta with horizontal. At the highest point of its
trajectory it splits into three segments of masses m, m and 2m. First part falls vertically
downward with zero initial velocity and second part returns via same path to the point of
projection. The velocity of third part of mass 2m just after explosion will be
a) U cos theta b) 3/2 u cos theta c) 2u cos theta d) 5/2 u cos theta

Answers

Answered by aman1091
13
correct option is (C)


.HOPE IT WILL HELP U
Attachments:
Similar questions