A projectile is fixed with a velocity u making an angle theta with the horizontal. Show its trajectory is a parabola. Derive an expression for 1) time of flight 2) maximum height 3) horizontal range.Please let me know the right answer.
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Explanation:
Use the equation y = 0.5 • g • t2 and substitute -9.8 m/s/s for g. The vertical displacement must then be subtracted from the initial height of 78.
Time Horizontal vertical
Displacement Displacement
1 s 20 m -4.9 m
-4.9 m2 s 40 m -19.6 m
-19.6 m3 s 60 m -44.1 m
-44.1 m4 s 80m -78.4 m
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