a projectile is given an initial velocity of (i+2j) m/s where I is along the ground and j is along vertical. if g=10m/s^2 the equation of trajectory is?
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Answered by
74
A particle is projected with velocity of (i + j) m/s.
so, horizontal component of velocity,
vertical component of velocity,
using formula for horizontal component,
here,
then, x = t ....(1)
applying formula for vertical component,
here,
so,
from equation (1),
this is the required equation of trajectory. here it is clear that equation is not other than parabola.
Answered by
53
Answer:
y=2x-5x²
Explanation:
Initial velocity V= i+2jm/s=Ux i + Uy j=ucos0 i+ usin90 j
then:
tan●=usin90/ucos0=2/1=2
Now:
equation of trajectory:
y = xtan● - 1/2( gx²/u²cos²90)
=> y= 2x-1/2[10x²/(ucos90)²]
=>y=2x-1/2[10x²/(1)²]
=>y=2x-5x²_________ans
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