Question

A projectile is given an initial velocity of i + 2j

. The Cartesian equation of its path is : (g = 10 m/s2

)

(Here, i



is unit vector along horizontal and j



is unit vector vertically upwards)​

Answer 1

Answer:

see the photo hope you will be able to understand.

Answer 2

Concept Introduction: Projectile Motion is motion in two dimensions.

Given:

We have been Given: Projectile Vector of initial velocity is

$i + 2j$

To Find:

We have to Find: The Cartesian Equation of the path.

Solution:

According to the problem, Velocity at X axis is

$x \: axis = 1m {s}^{ - 1}$

and the velocity in Y axis is

$y \: axis = 2m {s}^{ - 1}$

therefore

$x = v_{x}t \\ x = 1 \times t \\ x = t$

Now,

$y = v_{y}t + \frac{1}{2} a {t}^{2} \\ y = 2t - \frac{1}{2} \times 10 \times {t}^{2} \\y = 2t - 5 {t}^{2}$

now putting the value of x in the above equation we get,

$y = 2x - 5 {x}^{2}$

Final Answer: The Cartesian Equation of the path is

$y = 2x - 5 {x}^{2}$

#SPJ2