Question

A projectile is given an initial velocity of i + 2j. The cartesian equation of its path is (Take g = 10 ms^-2)

Answer 1

Using VECTOR sum, we can determine the magnitude of the velocity of projection of the projectile: radical 1 + 4 = radical 5.

Using arctan, we can determine the direction of the vector: arctan 2/1 = 63.43 degrees. The initial velocity therefore would be radical 5 at 63.43 d.

The Cartesian equation would be: y = 2 t - 5 t^2

The graph would be (plotted by personal graph app):

Answer 2

Answer:

Using VECTOR sum, we can determine the magnitude of the velocity of projection of the projectile: radical 1 + 4 = radical 5.

Using arctan, we can determine the direction of the vector: arctan 2/1 = 63.43 degrees. The initial velocity therefore would be radical 5 at 63.43 d.

The Cartesian equation would be: y = 2 t - 5 t^2

Explanation: